A car travels at a speed of 80 km/hr for 15 minutes and then at a speed of 40 km/hr for next 15 minutes. The average speed of the car is

15.7 m s^{- 1}

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16.7 m s^{- 1}

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17.7 m s^{- 1}

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18.7 m s^{- 1}

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Solution

The correct option is C $16.7 m s^{- 1}$
$Average speed = \frac{Total distance travelled}{Total time}$
$= \frac{80 \times \frac{1}{4} + 40 \times \frac{1}{4}}{\frac{2}{4}} = 30 \times 2 = 60 k m / h r$
$= 60 \times \frac{5}{18} = \frac{50}{3} m / s = 16.7 m / s$

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A car travels at a speed of 80 km/hr for 15 minutes and then at a speed of 40 km/hr for next 15 minutes. The average speed of the car is

The correct option is C 16.7ms−1Average speed=Total distance travelledTotal time =80×14+40×1424=30×2=60km/hr =60×518=503m/s=16.7m/s

The correct option is C $16.7 m s^{- 1}$
$Average speed = \frac{Total distance travelled}{Total time}$
$= \frac{80 \times \frac{1}{4} + 40 \times \frac{1}{4}}{\frac{2}{4}} = 30 \times 2 = 60 k m / h r$
$= 60 \times \frac{5}{18} = \frac{50}{3} m / s = 16.7 m / s$