A chord of a circle of radius 12 cm subtends an angle of 120 degrees. Find the area of the minor segment of the circle. (Use √3 = 1.732)

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Solution

Step 1: Find the area of the sector OAPB.

Step 2: Find the base and height of triangle OAB.

Step 3: Find the area of the triangle OAB.

Step 4: Area of the minor segment APB

$S o t h e a r e a o f t h e m i n o r s e g m e n t A P B i s e q u a l t o 88.38 c m^{2}$

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