-A- -B-A-A-B-B - A-A - B-

The correct option is A A [(A' ∪B') A]' =[(A' ∪B') ∩A']' (∵ A B=A ∩B') = [(A ∩ B)' ∩A']' (∵A'∪B'=(A ∩ B)' ) =[(A ∩ B)']'∪(A')' ...

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Complement of a Set

[(A' ∪B')-A]'...

Question

${[(A^{'} \cup B^{'}) - A]}^{'}$ =___

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B - A

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A - B

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|\begin{matrix} b^{2} - a b & b - c & b c - a c \\ a b - a^{2} & a - b & b^{2} - a b \\ b c - c a & c - a & a b - a^{2} \end{matrix}|

a b c (b - c) (c - a) (a - b)

(b - c) (c - a) (a - b)

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∆ A B O

\frac{1}{2} a b

\frac{1}{2} a^{2} b^{2}

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If A+B = $225^{\circ}$ , (1+cotA)(1+cotB) equal to

∣ ∣ ∣ ∣ \begin{matrix} a & b & b + c c & a & c + a b & c & a + b \end{matrix} ∣ ∣ ∣ ∣ = (a + b + c) (a - c)^{2}

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