A current carrying loop is placed in a uniform magnetic field in four different orientation:I,II, III & IV. Arrange them in the decreasing order of their potential Energy.
A
I > III > II > IV
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B
I > II >III > IV
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C
I > IV > II > III
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D
III > IV > I > II
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Solution
The correct option is CI > IV > II > III U=−MBcosθ; where θ= Angle between normal to the plane of the coil and direction of magnetic field.