Question

A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes.

Answer 1

Given,

Total distance covered $10m$ in $40sec$

So,

Total time taken $=2minc=120sec$

Total round completed = \dfrac{120}{40}=3 rounds

So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.

$A{C}^2=A{B}^2+B{C}^2$

$A{C}^2=(10{)}^2+(10{)}^2$

$A{C}^2=100+100$

$A{C}^2=200$

$AC=\sqrt{200}=10\sqrt{2}m$