The correct option is D Potential at A , B , C and O is same.
Given,
Inner radius of hollow conducting sphere r1=R
Outer radius of hollow conducting sphere r2=2R
From the figure, it is clear that VA=VB as points A and B lie on the same equipotential surface.
So, option (a) is correct answer.
For a hollow conducting sphere, Potential at any point inside the hollow sphere is same as the potential on its surface.
So, we can conclude from this fact that, V0=VC=VA=VB
Hence, options (a) and (d) are the correct alternatives.