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Byju's Answer

Standard XII

Physics

1st Equation of Motion

a particle is...

Question

a particle is projected upwards with a velocity of 100m/s at an angle of 60 with the vertical. find the time when the particle will move perpendicular to its intial direction, taking g

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Similar questions

Q. A particle is projected upwards with a velocity of

100 m/sec

at an angle of

60^{\circ}

with the vertical. Find the time when the particle will move perpendicular to its initial direction taking

g = 10 {m/sec}^{2}

A particle is projected upwards with a velocity of 100 m/s at an angle of 60°, with the vertical.
Then time taken by the particle when it will move perpendicular to its initial direction. Please explain and give answer.

Q. A particle is projected upwards with a velocity of

100 m / s e c

at an angle of

60^{0}

with the vertical. The time (in sec) when the particle will move perpendicular to its initial direction is 10x. (taking

g = 10 m / s e c^{2}

). The value of x is:

Q. A particle

A

is projected with an initial velocity of

60 m / s

at an angle

30^{\circ}

to the horizontal. At the same time, a second particle

B

is projected in direction as shown in figure with initial speed of

50 m / s

from a point at a distance of

100 m

from

A

. If the particles collide in air, find the time when the particles collide.

Q. A particle

A

is projected with an initial velocity of

60 m/s

at an angle

30^{\circ}

to the horizontal. At the same time a second particle

B

is projected in opposite direction with initial speed of

50 m/s

from a point at a distance of

100 m

from

A

. If the particles collide in air find the angle of projection

α

for particle

B

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