A particle moves with a velocity 5i-3j-6k- m-s under the influence of a constant force F-10i-10j-20k-N- The instantaneous power applied to the particle is

P=F⃗.V⃗=(5i̅ 3j̅+6k̅).(10i̅+10j̅+20k̅) =50 30+120=140 J/S ...

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Standard XI

Physics

Power, Force and Velocity

A particle mo...

Question

A particle moves with a velocity $5 ¯ i - 3 ¯ j + 6 ¯ k$ m/s under the influence of a constant force $\to F = (10 ¯ i + 10 ¯ j + 20 ¯ k)$ N. The instantaneous power applied to the particle is

200 J/S

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40 J/S

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140 J/S

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170 J/S

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Solution

The correct option is C 140 J/S
$p = \to F . \to V = (5 ¯ i - 3 ¯ j + 6 ¯ k) . (10 ¯ i + 10 ¯ j + 20 ¯ k) = 50 - 30 + 120 = 140 J / S$

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A particle moves with a velocity 5¯i−3¯j+6¯k m/s under the influence of a constant force →F=(10¯i+10¯j+20¯k)N. The instantaneous power applied to the particle is

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A particle moves with a velocity $5 ¯ i - 3 ¯ j + 6 ¯ k$ m/s under the influence of a constant force $\to F = (10 ¯ i + 10 ¯ j + 20 ¯ k)$ N. The instantaneous power applied to the particle is

The correct option is C 140 J/S
$p = \to F . \to V = (5 ¯ i - 3 ¯ j + 6 ¯ k) . (10 ¯ i + 10 ¯ j + 20 ¯ k) = 50 - 30 + 120 = 140 J / S$