A particle moves with a velocity 5-3-6-k-m-s under the influence of a constant force 1-0-1-0-2-0-k-N- The instantaneous power applied to the particle is-

The correct option is A 200 W P=F⃗.V⃗ #160; #160; =(5 î +3ĵ +6k̂).(10î+10ĵ+20k̂) #160; #160; =50+30+120 #160; #160; ...

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Standard XII

Physics

Second Law of Motion

A particle mo...

Question

A particle moves with a velocity $(^5 i +^3 j +^6 k) m / s$ under the influence of a constant force $(^10 i +^10 j +^20 k) N$ . The instantaneous power applied to the particle is:

200 W

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40 W

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140 W

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170 W

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Solution

The correct option is A $200 W$
$P = \to F . \to V$
$= (5^i + 3^j + 6^k) . (10^i + 10^j + 20^k)$
$= 50 + 30 + 120$
$= 200 W$

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A particle moves with a velocity (^5i+^3j+^6k)m/s under the influence of a constant force (^10i+^10j+^20k)N. The instantaneous power applied to the particle is:

The correct option is A 200WP=→F.→V =(5^i+3^j+6^k).(10^i+10^j+20^k) =50+30+120 =200 W

A particle moves with a velocity $(^5 i +^3 j +^6 k) m / s$ under the influence of a constant force $(^10 i +^10 j +^20 k) N$ . The instantaneous power applied to the particle is:

The correct option is A $200 W$
$P = \to F . \to V$
$= (5^i + 3^j + 6^k) . (10^i + 10^j + 20^k)$
$= 50 + 30 + 120$
$= 200 W$