A sample of coal gas contains 50%H2, 30%CH4, 14%CO and 6%C2H4. 100 mL of coal gas is mixed with 150 mL of O2 and the mixture is exploded. The volume of CO2 which will be formed (in ml) is :
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Solution
H2+12O2→H2O 50 mL CH4+2O2→CO2+2H2O 30 mL CO+12O2→CO2 14 mL C2H4+3O2→2CO2+2H2O 6 mL Volume of O2 required =502+30×2+142+6×3=25+60+7+18=110 mL. ∴ Volume of O2 left =150−110=40 mL. Volume of CO2 formed =30+ 14 + 6×2 =56 mL