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Question

A simple quick return mechanism is shown in the figure. The forward to return ratio of the quick return mechanism is 2 : 1. If the radius of the crank O1P is 125 mm, then the distance d (in mm) between the crank centre to lever pivot centre point should be

A
144.3
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B
216.5
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C
240.0
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D
250.0
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Solution

The correct option is D 250.0

O1P=125 mm
Quick return mechanism:

Time of working (forward) strokeTime of return stroke=βα

=360αα

21=360αα

2α=360oα

3α=360oα=120o

α2=60o

The extreme position of the crank (O1) is shown in figure.
From right angle triangle O2O1P1, we find that
sin(90oα/2)=O1P1O2P2

sin(90o60o)=125O1O2=125d
sin30o=125d

or d=125sin30o=250 mm

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