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Question

A sodium street light gives off yellow light that has a wavelength of 600 nm. Then
( h = 6.6×1034J.s)

A
Frequency of this light is 7×1014 s1
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B
Frequency of this light is 5×1014 s1
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C
Wavenumber of the light is 3×106 m1
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D
Energy of the photon is 5 eV
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Solution

The correct option is B Frequency of this light is 5×1014 s1
Given,
Wavelength of the light = 600 nm
We know,
hν=E
Frequency ν=cλ=3×108600×109=5×1014 Hz

Again,
wave number ν=1λ=1600×109=1.67×106 m1

So energy of the photon,
E=hν=(6.6×1034)(5×1014) J
=3.3×1019 J
=3.3×1019×6.2×1018 eV = 2.05 eV

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