Question 58 (a)

Subtract:

$- 7 p^{2} q r$ from $- 3 p^{2} q r .$

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Solution

We have,
$- 3 p^{2} q r - (- 7 p^{2} q r) = - 3 p^{2} q r + 7 p^{2} q r = p^{2} q r (- 3 + 7) = 4 p^{2} q r$
$[∵$ with -ve sign, +ve sign will be change]

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