Question

A verandah of width $2.25$m is constructed all along outside a room which is $5.5$m long and $4$m wide. Find

$\left(i\right)$ The area of the verandah.

$\left(ii\right)$ The cost of cementing the floor of the verandah at the rate of Rs $200$ per sq.m.

Answer 1

Given: Length of room $=5.5$m,

Width of room $=4$m,

Width of verandah which is constructed all along outside of room $=2.25$m,

Cost of cementing of verandha $=$ Rs $200$ per sq.m

$\therefore$, Length of room with verandah$=5.5+2.25+2.25=10$m

Width of room with verandah$=4+2.25+2.25=8.5$m

Area of room$=$Length$\times$Width$=5.5\times 4=22m^2$

Area of room with verandah$=$ Length$\times$Width$=10\times 8.5=85m^2$

Area of verandah$=$Area of room with verandah$-$Area of room$=85-22=63m^2$

Cost of cementing of verandah$=$Area$\times$Rate$=63\times$Rs.$200=$Rs.$12600$