Question

A verandah of width $2.25m$ is constructed all along outside a room which is $5.5m$ long and $4m$ wide. Find:

(i) the area of the verandah

(ii) the cost of cementing the floor of the verandah at the rate of $Rs.200$ per $m^2$.

Answer 1

(i) Length $\left(l\right)$ of room $=5.5m$

Breadth $\left(b\right)$ of room $=4m$

Area of the room $=l\times b=5.5\times 4=22m^2$

Now,

Length of the rectangle $EFGH$ so formed $=EF=5.5+2\times 2.25=10m$

And breadth of the rectangle $EFGH=FG=4+2\times 2.25=8.5m$

Therefore, area of the verandah $=$ Area of $EFGH-$ Area of the room

$=10\times 8.5-4\times 5.5$

$=85-22$

$=63m^2$

(ii)

Therefore cost of cementing the verandah $=63\times 200=Rs.12,600$