A wall 24 m long- 5 m high and 0-25 m thick is to be constructed using bricks measuring 25 cm -12-5 cm -7-5 cm- Find the number of bricks required- if 5- of the wall is occupied by cement and sand mixture-

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Volume of Regular Solids

A wall 24 m...

Question

A wall $24$ m long, $5$ m high and $0.25$ m thick is to be constructed using bricks measuring $25$ cm $\times 12.5$ cm $\times 7.5$ cm. Find the number of bricks required, if $5 %$ of the wall is occupied by cement and sand mixture.

12160

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12000

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12100

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12200

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Solution

The correct option is A $12160$
Dimensions of the wall: $24$ m long, $5$ m high and $0.25$ m thick.
Therefore, volume of wall $= l b h = 24 \times 5 \times 0.25 = 30 m^{3} = 30000000 {c m}^{3}$
Sand and mixture used $5 %$ of the wall volume.
The remaining volume is used for bricks is $30000000 - 30000000 \times \frac{5}{100} = 28500000$
Volume of bricks $= (25) (12.5) (7.5) = 2343.75$
$∴$ number of bricks required $= \frac{28500000}{2343.75} = 12160$

Hence, option A is the correct answer.

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A wall 24 m long, 5 m high and 0.25 m thick is to be constructed using bricks measuring 25 cm ×12.5 cm ×7.5 cm. Find the number of bricks required, if 5% of the wall is occupied by cement and sand mixture.

A wall $24$ m long, $5$ m high and $0.25$ m thick is to be constructed using bricks measuring $25$ cm $\times 12.5$ cm $\times 7.5$ cm. Find the number of bricks required, if $5 %$ of the wall is occupied by cement and sand mixture.