A weighing scale in a moving lift measures $47 N$ when a block of mass $4 k g$ is kept on it. If $g = 9.80 {ms}^{- 2}$ then acceleration of the lift is

9.80 {ms}^{- 2}

downwards

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9.80 {ms}^{- 2}

upwards

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1.96 {ms}^{- 2}

downwards

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1.96 {ms}^{- 2}

upwards

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Solution

The correct option is D $1.96 {ms}^{- 2}$ upwards
Here measured mass is higher than actual mass
So lift has to be accelerating up.
Given $\frac{N}{g} = 4.8 kg$
$\Rightarrow \frac{m (g + a)}{g} = 4.8$
$4 g + 4 a = 4.8 g$
$4 a = 0.8 g$
$\Rightarrow a = \frac{9.8}{5}$
$a = 1.96$

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A weighing scale in a moving lift measures 47 N when a block of mass 4 kg is kept on it. If g=9.80 ms−2 then acceleration of the lift is

The correct option is D 1.96 ms−2 upwardsHere measured mass is higher than actual mass So lift has to be accelerating up. Given Ng=4.8 kg ⇒m(g+a)g=4.8 4g+4a=4.8 g 4a=0.8 g ⇒a=9.85 a=1.96

A weighing scale in a moving lift measures $47 N$ when a block of mass $4 k g$ is kept on it. If $g = 9.80 {ms}^{- 2}$ then acceleration of the lift is

The correct option is D $1.96 {ms}^{- 2}$ upwards
Here measured mass is higher than actual mass
So lift has to be accelerating up.
Given $\frac{N}{g} = 4.8 kg$
$\Rightarrow \frac{m (g + a)}{g} = 4.8$
$4 g + 4 a = 4.8 g$
$4 a = 0.8 g$
$\Rightarrow a = \frac{9.8}{5}$
$a = 1.96$