ab2 is a factor of 4ab3−ab2+ab5.
True
False
We can write 4ab3−ab2+ab5 = ab2(4b−1+b3)
ab2 completely divides 4ab3−ab2+ab5 and hence a factor of 4ab3−ab2+ab5.
△ABC is constructed such that AB = 5 cm, BC = 12 cm and ∠B = 90∘. Then AC2 = AB2 + BC2.