Draw a line FL passing through E, parallel to B
⇒FL||AB||CD
Now ∠AFE=∠FEL (Alternate interior angles)
⇒∠FEL=55o Since AB||FL
Now ∠FEL+∠LEC=∠FEC
∠FEC+∠LEC=90o (∠FEC=90o(given))
⇒∠LEC=90o−55o
∠LEC=35o
∠LEC=∠ECP [Alternate interior angles]
∠ECP=35o
⇒a=∠ECP+∠PCD
a=35o+180o ([∠PCD=180o] ∠PCD angle is straight)
a=215o
![1181836_1299469_ans_7e4edc6f628a4974b7578fcbd883b951.jpg](https://search-static.byjusweb.com/question-images/toppr_invalid/questions/1181836_1299469_ans_7e4edc6f628a4974b7578fcbd883b951.jpg)