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Question

∆ABC ~ ∆LBN. In ∆ABC, AB = 5.1cm, ∠B = 40°, BC = 4.8 cm, ACLN=47. Construct ∆ABC and ∆LBN.

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Solution

Steps of Construction:

Step 1: Draw ∆ABC such that AB = 5.1 cm, ∠B = 40°, BC = 4.8 cm.

Step 2: Divide segment BC into 4 equal parts.

Step 3: Mark point N on ray BC such that length of BN is seven times of each part of segment BC.

Step 4: Draw a line parallel to side AC, through N. Name the point where the parallel line intersects ray BA as L.



Here, ∆ABC ~ ∆LBN.

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