MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Basic Proportionality Theorem

ABCD is a qua...

Question

ABCD is a quadrilateral in which the bisectors of angle-A and angle-C meet DC produced at Y and BA produced at X, respectively. Prove that angle-X+angle-Y=1/2(angle-A+angle-C)

Open in App

Solution

Suggest Corrections

thumbs-up

106

Similar questions

Q. In a quadrilateral ABCD, CO and DO are the bisectors of

∠ C

∠ D

respectively. Prove that

∠ C O D = \frac{1}{2} (∠ A + ∠ B)

A O

D O

are the bisectors of

∠ A

∠ D

of the quadrilateral

A B C D

∠ A O D = \frac{1}{2} (∠ B + ∠ C)

Q. A cyclic quadrilateral ABCD whose opposite sides when produced intersect at the [points P and Q]. The bisectors PF and QF of

∠ P

∠ Q

respectively at F
produce QF to meet AB at E. Prove that

∠ P F G = 90^{\circ}

Q. In a cyclic quadrilateral

A B C D

A B

D C

produced to meet at point

P

A D

B C

produced to meet at point

Q

P

Q

are outside the circle). Find the value of

∠ P T O

P T

Q T

are the bisectors of

∠ A P D

∠ A Q B

Q. Choose the correct option:
If the sides BA and DC of the parallelogram ABCD are produced as shown in figure then

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Basic Proportionality Theorem

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Basic Proportionality Theorem

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon