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Question

Add 2a+3b+c+d, a+bcd and 3a4b2c2d. [3 MARKS]

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Solution

Forming the equation : 1 Mark
Steps : 1 Mark
Result : 1 Mark

(2a+3b+c+d)+(a+bcd)+(3a4b2c2d)

2a+3b+c+da+bcd+3a4b2c2d

2aa+3a+3b+b4b+cc2c+dd2d

4a+0b2c2d

Sum =4a2c2d


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