Question

Allyl isocyanide has:

• A. $9\sigma$ and $4\pi$ bonds
• B. $8\sigma$ and $5\pi$ bonds
• C. $9\sigma ,3\pi$ and 2 non-bonding electrons
• D. $8\sigma ,3\pi$ and 4 non-bonded electrons

Answer 1

The correct option is C $9\sigma ,3\pi$ and 2 non-bonding electrons


The above structure of allyl isocyanide clearly shows $5C-H\left(\sigma \right),2C-C\left(\sigma \right),1C-N\left(\sigma \right),1N-C\left(\sigma \right),1C-C\left(\pi \right),2N-C\left(\pi \right)$ bonds, i.e., $9\sigma$ and $3\pi$ bonds in all. There are 2 non-bonded electrons on the C-atom (co-ordinate bond between N and C, the electron pair of N is shifted towards C. Hence, correct answer is option (c).