An electric dipole of length 4cm , when placed with its axis making an angle of 60∘ with a uniform electric field , experiences a torque of 4√3Nm. Find the potential energy of the dipole, if the dipole has charges of ±8nC (in J)
A
−2J
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B
+2J
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C
+4J
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D
−4J
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Solution
The correct option is D−4J Given,
Charge of dipole , q=±8×10−9C
Seperation between the charges 2a=4cmor0.04m
Torque acting on dipole τ=4√3Nm
Angle made by the axis of dipole with uniform electric field , θ=60∘
We know that,
Torque on the electric dipole is given by τ=pEsinθ
⇒E=τpsinθ=4√33.2×10−10×sin60∘
⇒E=4√3×23.2×10−10×√3=2.5×1010N/C
Potential energy of the electric dipole is U=−pEcosθ
Substituting the given data we get, U=−3.2×10−10×2.5×1010×cos60∘