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Question

An electric dipole of length 4 cm , when placed with its axis making an angle of 60 with a uniform electric field , experiences a torque of 43 Nm. Find the potential energy of the dipole, if the dipole has charges of ±8 nC (in J)

A
2 J
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B
+2 J
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C
+4 J
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D
4 J
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Solution

The correct option is D 4 J
Given,

Charge of dipole , q=±8×109 C

Seperation between the charges 2a=4 cm or 0.04 m

Torque acting on dipole τ=43 Nm

Angle made by the axis of dipole with uniform electric field , θ=60

We know that,

Torque on the electric dipole is given by τ=pEsinθ

E=τpsinθ=433.2×1010×sin60

E=43×23.2×1010×3=2.5×1010 N/C

Potential energy of the electric dipole is
U=pEcosθ
Substituting the given data we get,
U=3.2×1010×2.5×1010×cos60

U=3.2×2.5×0.5

U=4 J

Hence, option (d) is the correct answer.

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