An equi-convex lens of focal length ′f′ is cut into two parts along its principal axis, then
A
refractive index of the lens changes.
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B
radii of curvature of lens changes.
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C
intensity of image formed by each part will reduce to half.
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D
intensity of image formed by each part will becomes twice.
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Solution
The correct option is C intensity of image formed by each part will reduce to half. When an equi-convex lens of focal length ′f′ is cut into two parts along its principal axis, then
1. Refractive index μ of lens does not change. 2. Radii of curvature R1 and R2 of lens will not change. 3. Focal length of each part will be equal to that of initial lens. 4. Intensity of image formed by each part will reduce to half as the number of rays coming out of each part is half of the number that comes out of initial lens.