Question

An uncharged parallel plate capacitor is connected to a battery. The electric field between the plates is $10V/m$. Now a dielectric of dielectric constant $2$ is inserted between the plates filling the entire space. The electric field (in $V/m$) between the plates now is

Answer 1

Since the capacitor is connected to the battery, potential difference across the capacitor will remain same.
Electric field between plates ,
$E=\frac{V}{d}$
Where, $V=$ potential difference and $d$ is the perpendicular distance between the plates.
Thus, the electric field will remain unchanged.