Arrange the following compounds in the increasing order of polarity.

I < I I < I I I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I I < I I < I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I < I < I I I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

I I I < I < I I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $I I < I < I I I$

On polarisation of compound $I I$ , it becomes anti-aromatic in nature which destabilises it. Therefore, its polarity or dipole moment is the lowest.

Compound $I I I$ on polarisation attains aromaticity which stabilises it, so it has the highest dipole moment.

The order of polarity is: $I I < I < I I I$

Suggest Corrections

Similar questions

C H_{3} O N a

Arrange the following compounds in increasing order of their boiling points.

(a) (ii) < (i) < (iii) (b) (i) < (ii) < (iii)

Arrange the following compounds in the increasing order of their densities.

(a) (i) < (ii) < (iii) <(iv) (b) (i) < (iii) < (iv) < (ii)

Join BYJU'S Learning Program