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First Order Reaction

Atomic weight...

Question

Atomic weight of Boron is 10.81 and it has 2 isotopes 5B10 and 5B11, then the ratio of 5B10:5B11 in nature would be 1. 15:16 2. 10:11 3. 19:81 4. 81:19

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Q. Atomic weight of boron is

10.81

and it has two isotopes

_{5} B^{10}

_{5} B^{11}

. Then ratio of

_{5} B^{10} :_{5} B^{11}

in nature would be

Q. The percentage of two stable boron isotopes

_{5} B^{11}

_{5} B^{10}

is, given that average atomic mass of boron is 10.81amu.

Q. Atomic weight of boron is

10.81

and it has two isotopes

\frac{10}{5} B

\frac{11}{5} B

in nature would be :

Boron has two stable isotopes,

^{10} B (19 %)

^{11} B (81 %)

. Average atomic weight for boron in the periodic table is:

Q. Boron has two isotopes,

_{5} B^{10}

_{5} B^{11}

and the atomic weight of boron is

10.81

_{5} B^{10} :_{5} B^{11}

in nature would be:

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