wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve

abxbay=a+b

axby=2ab


Open in App
Solution

We have,

abxbay=a+b ........(1)

axby=2ab ..........(2)

Dividing equation (2) by 'a' on both sides

xbay=2b .............(3)

Subtracting equation (3) from equation (1), we get

(ab1)x=ab

(ab)bx=ab

x=(ab)bab)

x=b

Now,

Dividing equation 2 by 'b' on both, we get

abxy=2a .........(4)

Subtraction equation 4 from equation 1, we get

(1ba)y=ba

(aba)y=ba

y=a(ba)(ab)

y=a

x=b and y=a


flag
Suggest Corrections
thumbs-up
255
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basics Revisted
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon