BALANCE THIS GIVEN EQUATION BY THE HELP OF THE ALTERNATE WAY OF BALANCING NOT THE TRADITIONAL WAY BY SHOWING THE APPROPRIATE STEPS ELABORATELY. EQN :- Ba(OH)2 + NH4Cl ---> BaCl2 + NH3 + H2O

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When Ba(OH)₂ is mixed with NH₄Cl then why BaCl₂, NH₃ and H₂O is formed and not BaCl₂and NH₄OH?

M n O_{2} + H C l \to M n C l_{2} + C l_{2} + H_{2} O

N H_{4} C l + C a (O H)_{2} \to N H_{3} + C a C l_{2} + H_{2} O

B a C l_{2} + A l_{2} (S O_{4})_{3} \to B a S O_{4} + A l C l_{3}

N a A l O_{2} + H_{2} O + C O_{2} \to A l H_{3} + N a_{2} C O_{3}

N H_{3} + O_{2} \to N O + H_{2} O

Z n + H N O_{3} \to Z n (N O_{3})_{2} + N O_{2} + H_{2} O

H_{2} S + O_{2} \to H_{2} O + S O_{2}

P b O + C \to P b + C O_{2}

B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + H C l

C H_{4} + O_{2} \to C O_{2} + H_{2} O

Balance the following equation b hit and trial method :. NH4Cl + Ca(OH)2 ------------> CaCl2 + H2O + NH3

N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + N H_{3} + H_{2} O

H g_{2} C l_{2} + N H_{3} \to H g + H g N H_{2} C l + N H_{4} C l

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