Based on the information given below, mark the correct option.
Information: On adding acetone to methanol, some of the hydrogen bonds between the methanol molecules break.
Based on the information given below, mark the correct option.
Information: On adding acetone to methanol, some of the hydrogen bonds between the methanol molecules break.
Minimum boiling azeotropes are those which boil at a lower temperature than the boiling points of each component in their pure state.
Minimum boiling point azeotropes are non-ideal binary solutions that show positive deviation from Raoult’s law.
Since they show a positive deviation, the \(A-B\) interactions are weaker than those between \(A-A~\text{or}~B-B\), which signifies that the resulting force of attraction between the molecules after mixing becomes weaker.
Maximum boiling azeotropes are those which boil at a higher temperature than the boiling points of each component in their pure state.
Maximum boiling point azeotropes are non-ideal binary solutions that show negative deviation from Raoult’s law.
Since they show negative deviation, the \(A-B\) interactions are stronger than those between \(A-A~\text{or}~B-B\), which signifies that the resulting force of attraction between the molecules after mixing are stronger.
In its pure state, methanol molecules are strongly bonded through hydrogen bonding and when acetone is added to this solution, acetone molecules get in between the molecules of methanol and break some of the hydrogen bonds.
Therefore, the resulting intermolecular attractions between acetone and methanol are weaker. Thus, this shows a positive deviation from Raoult’s law.
Since, the mixture is showing positive deviation from Raoult’s law, at a specific composition, methanol-acetone mixture will form a minimum boiling azeotrope.
Hence, option (A) is correct.
Minimum boiling azeotropes are those which boil at a lower temperature than the boiling points of each component in their pure state.
Minimum boiling point azeotropes are non-ideal binary solutions that show positive deviation from Raoult’s law.
Since they show a positive deviation, the \(A-B\) interactions are weaker than those between \(A-A~\text{or}~B-B\), which signifies that the resulting force of attraction between the molecules after mixing becomes weaker.
Maximum boiling azeotropes are those which boil at a higher temperature than the boiling points of each component in their pure state.
Maximum boiling point azeotropes are non-ideal binary solutions that show negative deviation from Raoult’s law.
Since they show negative deviation, the \(A-B\) interactions are stronger than those between \(A-A~\text{or}~B-B\), which signifies that the resulting force of attraction between the molecules after mixing are stronger.
In its pure state, methanol molecules are strongly bonded through hydrogen bonding and when acetone is added to this solution, acetone molecules get in between the molecules of methanol and break some of the hydrogen bonds.
Therefore, the resulting intermolecular attractions between acetone and methanol are weaker. Thus, this shows a positive deviation from Raoult’s law.
Since, the mixture is showing positive deviation from Raoult’s law, at a specific composition, methanol-acetone mixture will form a minimum boiling azeotrope.
Hence, option (A) is correct.
