Calculate the number of atoms in 46g of Na.

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Solution

Molar mass of Na = 23g , Given mass = 46g
$N o . o f m o l e s = \frac{N o . o f a t o m s}{A v a g a d r o n u m b e r (N_{A})} = \frac{G i v e n m a s s}{M o l a r m a s s}$
$N o . o f a t o m s = \frac{G i v e n m a s s \times N_{A}}{M o l a r m a s s}$
= $\frac{46 \times 6.022 \times 10^{23}}{23}$
= $2 \times 6.022 \times 10^{23}$
= $12.044 \times 10^{23}$ atoms
∴ 46 g of Na contains $12.044 \times 10^{23}$ atoms

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