$C H_{3} - C \equiv C - C H_{3} (1) H_{2} / P d / C a C O_{3} o r B a S O_{4} - ---------------- \to (2) B r_{2}, C C l_{4} X$

2,3-Dibromobutane

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1,3-Dibromobutane

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2-bromobutane

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All of the above.

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Solution

The correct option is A 2,3-Dibromobutane
In presence of lindlar's catalyst, alkynes undergoes partial reduction. the addition of the hydrogen substituent always proceeds via syn addition (addition of the substituent on the same side of the bond). Therefore, the final product is purely cis-isomer of the alkene.
Halogens like bromine and chlorine add up to alkene to form vicinal dihalides

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Similar questions

C H_{3} - C \equiv C - C H_{3} (1) H_{2} / P d / C a C O_{3} o r B a S O_{4} - ---------------- \to (2) B r_{2}, C C l_{4} X

C H_{3} C \equiv C C H_{3} i) X - --- \to i i) \frac{H_{2} O}{Z n} C H_{3} - C | O - C | O - C H_{3}

In the reaction of $C H_{2} - C H_{2} - C C l_{2} - C H_{3} X - \to C H_{3} - C \equiv C - C H_{3}$ the reagent 'X' is

S_{N} 1

C H_{3} X, C H_{3} - C H_{2} - X, C H_{3} - C | X H - C H_{3}, C H_{3} - C H_{3} | C | C H_{3} - X,

(X = S a m e)

C H_{3} - N H - O | | C - C H_{3} L A H - -- \to X

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