Question

$C{H}_{3}CHO+HCN\to C{H}_{3}CH\left(OH\right)CN\underset{H_{2}O}{\overset{H^{+}}{\to }}C{H}_{3}CH\left(OH\right)COOH$

In the reaction, an asymmetric centre is generated. The acid obtained would be:

• A. 20% $d$ + 80% $l$ -isomer
• B. $d$-isomer
• C. $l$-isomer
• D. 50% $d$ + 50% $l$-isomer

Answer 1

The correct option is D 50% $d$ + 50% $l$-isomer