Question

Chlorobenzene on reaction with $C{H}_{3}Cl$ in presence of anhydrous $AlC{l}_3$ gives predominantly :

• A.
• B.
• C.
• D. None of the above

Answer 1

The correct option is A

Friedel Craft's Alkylation:
Chlorobenzene on reaction with $C{H}_{3}Cl$ in presence of anhydrous $AlC{l}_3$ forms para substituted methyl as major product i.e. $\text{4-methylchlorobenzene}$.
Since, $C{l}^{-}$ group attached to benzene is ortho and para directing, so it forms $o-$ and $p-$ chloronitrobenzene as products in electrophilic substitution reaction of chlorobenzene.
Here the major product is p-methylchlorobenzene because ortho is disfavourd due to steric hindrance. Hence correct option is a.