The correct option is D All of the above.
Alkali earth metals have the general electronic configuration of ns2. Here the outer s-shell is fully filled and also the size of element will decrease while moving across the period due to higher effective nuclear charge, this makes the electron to held firmly with nucleus. thus the ionisation energy will be higher to remove a electron from fully filled s-orbital. Hence Ionization energy of alkaline earth metals is greater than that of alkali metals.
Ionic and Atomic radius increases down the group of the periodic table, both radii will be smaller than the alkali metal and larger than other atoms of the same period due to charge and addition of the electron to the same energy level.
Hence, d is the correct option.