Solution:
Isoelectronic Species:
The species with same number of electrons are called isoelectronic species.
Number of electrons of \('C' = 6\)
Number of electrons of \('N' = 7\)
Number of electrons of \('O' = 8\)
Number of electrons of \('Cl' = 17\)
Number of electrons of \('Sn' = 50\)
Total number of electrons of \(NO^{+}~=~7+8-1=14\)
Total number of electrons of \(N_{2}=7+7=14\)
Total number of electrons of \(SnCl_{2}\)
\(=50+2\times17=84\)
Total number of electrons of \(NO^{-}_{2}\)
\(=7+8\times2+1=24\)
\(NO^{+}\text{and}~N_{2}\) have the same number of electrons, thus they are isoelectronic species. The correct answer are options (A) and (B).