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Electronegativity and Hybridisation

Compare bond ...

Question

Compare bond angle of OSF4,CH2SF4,SF4 OCl2,O2Cl,OCl2-(popular one) Explain the reasons considered

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I	II
$O C l_{2}$	$O F_{2}$

The bond angle is greater in

O C l_{2}

O F_{2}

because there is some

π

interactions in

O C l_{2}

involving donation from the filled p-orbitals on oxygen into the empty d-orbitals on chlorine No

π

-bonding is possible for

O F_{2}

because all orbitals are filled on both atoms.
If true enter 1, else enter 0.

Q. The sequence that correctly represents the increasing order of bond angles in

O F_{2}, O C l_{2}, C l O_{2}

H_{2} O

Q. The incorrect statement regarding

O (S i H_{3})_{2}

O C l_{2}

molecule is/are :

Q. Find the total number of species having bent shape.

I_{3}^{-}, N O_{2}^{+}, H_{2} S, O C l_{2}, X e F_{2}, S O_{2}, N O C l

Q. Give reason all bonds in

{S F}_{4}

are not equivalent.

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Electronegativity and Hybridisation

Standard XII Chemistry

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