Consider I2Cl6 compound and calculate the value of (x+y)÷z
Where : x= Total no. of (2C–2e–) bond y= Total no. of (3C–2e–) bond z= Total no. of (3C–4e–) bond
A
2
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B
2.0
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Solution
x= Total number of (2c−2e−) bond =4 y= Total number of (3c−2e−) bond =0 z= Total number of (3c−4e−) bond =2 x=4,y=0,z=2
The value of =(4+0)2=2