Question

Consider the diode circuit shown in the circuit below:



If the diode is ideal then the value of current flowing through the diode is equal to

• A. 5 mA
• B. 2.5 mA
• C. 1.5 mA
• D. 0.5mA

Answer 1

The correct option is D 0.5mA

Drawing the Thevanin's equivalent of the linear circuit, we get



$\therefore I=\frac{20-15}{10k\Omega }=0.5mA$