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Question

Consider two right-angled triangles inscribed in a square such that their hypotenuse intersect at a point O inside the square. What is the angle between the hypotenuse of the triangle and the base of the square?


A

30

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B

90

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C

45

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D

60

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Solution

The correct option is C

45


In the square ABCD, we have right-angled triangles, ADC and BCD such that their hypotenuse intersect at the point O inside the square.

Now, since the diagonals of a square are equal in length, and every angle is a right angle, we have

BD=AC and B=90.

Thus, BDC is a right-angled isosceles triangle.

BDC=45 .....(Sum of angles of a triangle is 180)


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