Question

Construct $∆\mathrm{ABC}$, given $\mathrm{m}\angle \mathrm{A}=60°,\mathrm{m}\angle \mathrm{B}=30°$and $\mathrm{AB}=5.8\mathrm{cm}$.

Answer 1

First we draw a rough sketch

The steps for construction are given below:

Step1: Constructing an angle of $60°$

Draw a line segment $\mathrm{AB}=5.8\mathrm{cm}$.

From point A, draw a ray to make an angle of $60°$ i.e. $\angle \mathrm{A}=60°$.

Step 2: Constructing an angle of $30°$

From point B, draw an another ray making an angle of $30°$ i.e. $\angle B=$ $30°$.

Step 3: Constructing the $∆\mathrm{ABC}$

Let point C be the point where the two rays intersect.

Thus, $∆\mathrm{ABC}$ is the required triangle.