Question

Convert $\frac{1+7i}{(1-i{)}^2}$ into $a+ib$ form.

Answer 1

Now,

$\frac{1+7i}{(1-i{)}^2}$

$=\frac{1+7i}{-2i}$ [ Since $(1-i{)}^2=-2i$]

$=-\frac{7}{2}+i\frac{1}{2}$.

This is the required $a+ib$ form.