Copper sulphate on treatment with potassium iodide precipitates cuprous iodide, liberates iodine gas and also forms potassium sulphate. Write a balanced equation for the mentioned reaction.

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Solution

The reaction is given by: $C u S O_{4} + K I \to C u I + I_{2} + K_{2} S O_{4}$
After balancing it becomes: $2 C u S O_{4} + 4 K I \to 2 C u I + I_{2} + 2 K_{2} S O_{4}$

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Write the balanced chemical equations for the following reactions-

(a) Sodium carbonate on reaction with hydrochloric acid in equal molar concentration gives sodium chloride and sodium hydrogen carbonate.

(b) Sodium hydrogen carbonate on reaction with hydrochloric acid gives sodium chloride, water and liberates carbon dioxide.

(c) Copper sulphate on treatment with potassium iodide precipitates cuprous iodide $({Cu}_{2} I_{2})$ , liberates iodine gas and also forms potassium sulphate.

Q. Question 20.3

Write the balanced chemical equation for the following reaction and identify the type of reaction.

Chlorine gas is passed in an aqueous potassium iodide solution to form potassium chloride solution and solid iodine.

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Copper sulphate on treatment with potassium iodide precipitates cuprous iodide, liberates iodine gas and also forms potassium sulphate. Write a balanced equation for the mentioned reaction.

The reaction is given by: CuSO4+KI→CuI+I2+K2SO4 After balancing it becomes: 2CuSO4+4KI→2CuI+I2+2K2SO4

The reaction is given by: $C u S O_{4} + K I \to C u I + I_{2} + K_{2} S O_{4}$
After balancing it becomes: $2 C u S O_{4} + 4 K I \to 2 C u I + I_{2} + 2 K_{2} S O_{4}$