The correct option is A cos^2 A sin^2 B nbsp;= cos(A + B). Cos(A B) ∴ cos^2 48^∘ sin^2 12^∘ = cos60^∘ . cos 36^∘ =1 2(√(5)+1/4)=√(5)+1/8 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Cos(A+B)Cos(A-B)

cos 2 48∘-sin...

Question

$c o s^{2} 48^{\circ} - s i n^{2} 12^{\circ} =$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B

$c o s^{2} A - s i n^{2} B$ = cos(A + B). Cos(A - B)

$∴ c o s^{2} 48^{\circ} - s i n^{2} 12^{\circ} = c o s 60^{\circ} . c o s 36^{\circ}$

= $\frac{1}{2} (\frac{\sqrt{5} + 1}{4}) = \frac{\sqrt{5} + 1}{8}$

Suggest Corrections

Similar questions

c o s^{2} 48^{\circ} - s i n^{2} 12^{\circ}

({cos}^{2} 66^{\circ} - {sin}^{2} 6^{\circ}) ({cos}^{2} 48^{\circ} - {sin}^{2} 12^{\circ})

{cos}^{2} 48^{\circ} - {sin}^{2} 12^{\circ}

{cos}^{2} 48^{\circ} - {sin}^{2} 12^{\circ}

{cos}^{2} 48^{\circ} - {sin}^{2} 12^{\circ} = \frac{\sqrt{5} + 1}{8}

Join BYJU'S Learning Program