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Introduction to Imperfections in Solids

CsCl crystall...

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CsCl crystallizes in a cubic cell that has a Cl^- at each corner and Cs^+ at the center of the unit cell ,if radius of Cs^+is 1.69A^o and r_{Cl}=1.81 A^o,what is the edge lenght of unit cell

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C s C l

crystallizes in a cubic lattice that has a

C l^{-}

at each corner and

C s^{+}

at the centre of the unit cell. If

(r_{C s^{+}}) = 1.69 o A

(r_{C l^{-}}) = 1.81 o A

, what is the value of edge length a of the cube?

Q. If the length of the body diagonal for CsCl which crystallizes into a cubic structure with

C l^{-}

ions at the corners and

C s^{+}

ions at the centre of the unit cells is

7 ˚ A

and the radius of the

C s^{+}

1.69 ˚ A

, what is the radius of

C l^{-}

˚ A

?

C s C l

has body-centered cubic arrangement. Reason:

C s C l

C s^{+}

8 C l^{-}

ions in its unit cell.

Q. If the length of body diagonal for

CsCl

, which crystallises into a cubic structure with

{Cl}^{-}

ions at the corners and

{Cs}^{+}

ions at the centre of unit cell is

7 ˚ A

and the radius of

{Cs}^{+}

1.69 ˚ A

. The radius of

{Cl}^{-}

Q. If the ionic radius of $Cs^+$ and $Cl^-$ are

1.69 ˚ A

1.81 ˚ A

respectively, the edge length of the unit cell is:

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