Cu2S+(SO4)-2=Cu+2 + (SO3)-2. Balance this Redox reaction by Half reaction method

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Write the balanced redox reaction.

C u^{2 +} + S O_{2} \to C u^{+} + {S O}_{4}^{2 -}

Q. Balance the redox reaction by Half reaction method.

{F e}^{2 +} (a q) + {C r}_{2} O_{7}^{2 -} (a q) (acid medium) - ------- \to {F e}^{3 +} (a q) + {C r}^{3 +} (a q)

The $E^{\circ}$ for $C u^{2 +} / C u^{+}$ ; $C u^{+} / C u$ , $C u^{2 +} / C u$ are 0.15V, 0.50 V and 0.325 V respectively. The redox cell showing redox reaction $2 C u^{+} \to C u^{2 +} + C u$ is made. The $E^{\circ}$ of this cell reaction and $Δ G^{\circ}$ may be:

Q. The

E^{⊖} f o r C u^{2 +} / C u^{\oplus}, C u^{\oplus} / C u, C u^{2 +} / C u,

are 0.15 V, 0.50 V, and 0.325 V, respectively. The redox cell showing redox reaction

2 C u^{+}, \to C u^{2 +} + C u

is made.

E^{⊖}

of this cell reaction and

Δ G^{⊖}

may be :

Two half reactions for the following equation are:
$4 H_{2} S O_{4} + K_{2} C r_{2} O_{7} + 3 N a_{2} S O_{3} ⟶ C r_{2} (S O_{4})_{3} + K_{2} S O_{4} + 3 N a_{2} S O_{4} + 4 H_{2} O$

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