ddx( sec2 x + cosec2 x)=
4 cosec 2x cot 2x
-4 cosec 2x cot 2x
4 cosec x cot 2x
None of these
Finding the value of
Given, y = ( sec2 x + cosec2 x)
= 1cos2x + 1sin2 x = sin2 x +cos2 xcos2 x sin2 x = 1cos x sin x = 2sin 2x = 2 cosec 2x
Differentiate it with respect to x, we get
dydx = 2 ×-cosec 2x cot 2x ×2 = -4 cosec 2x cot 2x
Hence, option (B) is correct.