D-(+)-glucose reacts with hydroxyl amine and yield an oxime. The structure of the oxime would be:

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Solution

The correct option is D
D-(+)-glucose reacts with hydroxyl amine and yield an oxime.
In this reaction, the aldehyde group reacts with hydroxyl amine to form $C H = N O H$ group known as oxime group.

This confirms the presence of carbonyl group $(> C = O)$ . Hence option (d) is correct.

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Q. D(+) - glucose reacts with hydroxyl amine and yields an oxime. The structure of the oxime would be

Q. D-(+)-glucose reacts with hydroxyl amine and yield an oxime. The structure of the oxime would be:

Q. D(+) - glucose reacts with hydroxyl amine and yields an oxime. The structure of the oxime would be

Which of the following reactions of glucose can be explained only by its cyclic structure?
(a) Glucose forms pentaacetate
(b) Blucose reacts with hydoxylamine to form an oxime
(c) Pentaacetate of glucose does not reach with hydroxyl amine
(d) Glucose is oxidised by nitric acid to gluconic acid

The smallest ketone and its next homologue are reacted with NH2OH to form oxime. What will be the result?

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D-(+)-glucose reacts with hydroxyl amine and yield an oxime. The structure of the oxime would be:

The correct option is D D-(+)-glucose reacts with hydroxyl amine and yield an oxime. In this reaction, the aldehyde group reacts with hydroxyl amine to form CH=NOH group known as oxime group. This confirms the presence of carbonyl group (>C=O). Hence option (d) is correct.

The correct option is D
D-(+)-glucose reacts with hydroxyl amine and yield an oxime.
In this reaction, the aldehyde group reacts with hydroxyl amine to form $C H = N O H$ group known as oxime group.

This confirms the presence of carbonyl group $(> C = O)$ . Hence option (d) is correct.