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Question

ΔGo for 12N2(g)+32H2(g)NH3(g) is 16.5kJ mol1. Find out Kp for the reaction at 25oC. Also report Kp and ΔGo for N2(g)+3H2(g)2NH3(g) at 25oC.

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Solution

For the reaction
12N2(g)+32H2(g)NH3(g)
logKp=ΔGo2.303RT
logKp=(16.5×103J/mol)2.303×8.314J/mol/K×298K
logKp=2.8917
Kp=779.41
For the reaction N2(g)+3H2(g)2NH3(g)
Kp is equal to the square of the value of Kp for the first reaction. It is equal to (779.41)2=6.07×105
ΔGo=2.303×8.314J/mol/K×298Klog6.07×105
ΔGo=32998Jmol1
ΔGo=32.9kJmol1
(1kJ=1000J)

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